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The chemical equation below shows the combustion of methane (CH4).

CH4 + 2O2 -> CO2 + 2H2O

The molar mass of oxygen gas (O2) is 32.00 g/mol. The molar mass of carbon dioxide (CO2) is 44.01 g/mol. What mass of CO2, in grams, will form when 8.94 g O2 completely react?

a: 3.25
b: 6.15
c: 13.0
d: 53.0

Respuesta :

According to the chemical equation, the reaction ratio between O2 and CO2 is 2:1, which mean for every 2 moles of O2 reacted there is 1 mole of CO2 formed. 

Use the molar mass and mass of O2 to find out the moles of O2: moles of O2 = mass of O2/molar mass of O2 = 8.94g/32.00g/mol = 0.2794 mole.  Therefore, the moles of CO2 that formed is 0.2794moles/2 = 0.1397 mole

Use the moles and molar mass CO2 to find out the mass of CO2:
Mass of CO2 = moles of CO2 * molar mass of CO2 = 0.1397 mole * .44.01g/mole = 6.15 g.

So the answer is B 6.15g.
Martebi

There are ways to calculate molar mass. The mass of CO2 is 6.15.

What is molar mass?

Molar mass is known to be defined commonly as the mass in grams of one mole of a specific substance/compounds. The units of molar mass is often done in grams per mole (g/mol).

Based on the chemical equation, the reaction ratio between O2 and CO2 is said to be in the ration of 2 : 1.

Where there is 2 moles of O2 and 1 mole of CO2 created.

By Using the molar mass and mass of O2 to look for the moles of O2, It is therefore:

8.94g/32.00g/mol = 0.2794 mole.  So the moles of CO2 that is formed  from 0.2794moles/2  is 0.1397 mole

Later on, you have to use the moles and molar mass CO2 to know the mass of CO2. So;

Mass of CO2 = moles of CO2 multiplies molar mass of CO2 = 0.1397 mole x 44.01g/mole will give you  6.15 g.

Therefore  option  B  is correct.

Learn more about  molar mass from

https://brainly.com/question/18142599

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