Answer:
[tex](\frac{1}{2},1)[/tex] does not lie on the graph.
Step-by-step explanation:
Options given by you are [tex](-\frac{1}{2}, -3), (\frac{1}{2}, 1)[/tex] and (-1, -4)
Equation of the line is y = 2x - 2 and we will plug in the values to check whether these points lie on the line or not.
For ([tex](-\frac{1}{2},-3)[/tex]
-3 = [tex]-\frac{2}{2}-2[/tex]
-3 = -1 - 2
-3 = -3
So this point lies on the line.
For [tex](\frac{1}{2},1)[/tex],
1 = [tex]\frac{2}{2}-2[/tex]
1 = 1- 2
1 = -1
But 1 ≠ -1
Therefore, the point ([tex]\frac{1}{2}, 1[/tex]) lies on the line.
For (-1 , -4)
-4 = 2(-1) - 2
-4 = -2 - 2
-4 = -4
So this point lies on the line.
Therefore, [tex](\frac{1}{2},1)[/tex] doesn't lie on the graph of the line.
