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At intermission, Xavier sold refreshments. Of the items he had, 1/5 were granola bars and 1/2 the remaining items were containers of popcorn. The rest were divided equally among apples, rice cakes, and containers of yogurt. Xavier sold the 8 apples he had. How many items did he originally have?

Respuesta :

The answer to this word problem is 60 items, if you want to see how I solved it, just let me know.

Answer: There are 80 items he originally have.

Step-by-step explanation:

Since we have given that

Part of refreshments were granola = [tex]\dfrac{1}{5}[/tex]

Part of refreshments were popcorns = [tex]\dfrac{1}{2}[/tex]

Remaining part would be

[tex]1-(\dfrac{1}{5}+\dfrac{1}{2})\\\\=1-\dfrac{7}{10}\\\\=\dfrac{10-7}{10}\\\\=\dfrac{3}{10}[/tex]

Since rest were divided equally among apples, rice cakes, and yogurt.

Number of apples sold = 8

Let the total number of items be 'x'.

According to question, it becomes,

[tex]\dfrac{3}{10}\times \dfrac{1}{3}x=8\\\\\dfrac{x}{10}=8\\\\x=80[/tex]

Hence, there are 80 items he originally have.

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