a gas has a pressure of 710 kpa at 227 c what will its pressure be at 27 c if the volume does not change

First, we should convert our temperature values from celsius to kelvin. By adding 273.15K to all of the temperature values, we now have 500.15K and 300.15K. Now, we must plug our known values into Gay-Lussac's law (P1/T1 = P2/T2). This gives us 710kPa/500.15K = x/300.15K. Now, we simply solve for x, which gives us an answer of x = 426 kPa.

Hope this helps!

Answer Link

keshavgandhi04 keshavgandhi04 · Answer 2 · 2022-05-31T10:28:42+02:00

We have to calculate the final pressure of the gas, given its change in temperature and the fact that its volume doubled.

We can solve this problem using the combined gas law:

What is the combined gas law?

It states that the ratio of the product of pressure and volume and the absolute temperature of a gas is equal to a constant.

P1V1/T1 = P2V2/T2

By converting our given temperatures to Kelvin, which we always must do for gas equations:

T1 = 227o C + 273 = 500K

T2 = 27.0o C + 273 = 300K

As above not given any values for the volume, but we know that V2 is twice that of V1, let's make things as simple as possible by making V1 1 liter and V2 2liters.

Plugging in our known values, and rearranging the equation to solve for the final pressure, P2, we have

P2 = P1 V1 T2 /T1V2

= ( 710 kPa) (1L) (300K) / (500K) (2L)

= 213 kPa

Thus the final pressure is 213 kilopascals.

For more information regarding combined gas law, visit:

https://brainly.com/question/15331536

#SPJ2