Select the equation in which the graph of the line has a positive slope, and the y-intercept equals -5. 10x – 5y = 40 5x – 10y = –12 5x + y = 50 x – 2y = 10
The equation x-2y=10 fits the requirements. To figure this out, I put them all in point-slope intercept form: y=mx+b x-2y=10 -x -x -2y=-x+10 --------------- -2 -2 y=x/2-5 x/2: positive! -5: correct y-interecpt!
