Respuesta :
We have:
[tex]-1=5x^2-2x\\\\5x^2-2x+1=0[/tex]
so:
[tex]a=5\qquad b=-2\qquad c=1[/tex]
and discriminant:
[tex]\Delta=b^2-4ac=(-2)^2-4\cdot5\cdot1=4-20=\boxed{-16\ \textless \ 0}[/tex]
Discriminant is negative so there are no real solutions.
[tex]-1=5x^2-2x\\\\5x^2-2x+1=0[/tex]
so:
[tex]a=5\qquad b=-2\qquad c=1[/tex]
and discriminant:
[tex]\Delta=b^2-4ac=(-2)^2-4\cdot5\cdot1=4-20=\boxed{-16\ \textless \ 0}[/tex]
Discriminant is negative so there are no real solutions.