Respuesta :

RickyChen
I see your last line is : c(x) = 0.9(x^2-10)^2 + 101.1

Let y = x^2, then c(y) = 0.9(y-10)^2 + 101.1

Apparently, c(y) is a parabola, min is 101.1 when y = 10, max is infinity

So let x^2 = 10 -> x = sqrt(10) or -sqrt(10), min is 101.1, max is infinity

Answer:

the min is 101.1

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