Hey there!
If I understand your problem correctly, the probability that mail is delivered before 2 PM is 0.09, or 9%. Let me know if this inaccurate and I'd be glad to help you out further.
Because these events are independent (meaning that one doesn't depend on the other for results), you can use the following formula:
→ P(A ∩ B) = P(A) • P(B)
P(A ∩ B) is the combined probability of both events, P(A) is the probability of the mail getting delivered on day 1 before 2 PM, and P(B) is the same for day 2 as day 1.
So, you could plug in your information like this:
→ P(A ∩ B) = 0.09 • 0.09
→ P(A ∩ B) = 0.0081
You would then multiply this decimal by 100 to get the percentage.
→ 0.0081 • 100 = 0.81%
There's a 0.81% chance that the mail will be delivered before 2 PM on both days. Pretty slim chance!
Hope this helped you out! :-)
