the distacne between the points (x1,y1) and (x2,y2) is
[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
so the distance between (4,5) and (10,13) is
well, first
x1=4
y1=5
x2=10
y2=13
so
[tex]D=\sqrt{(10-4)^2+(13-5)^2}[/tex]
[tex]D=\sqrt{(6)^2+(8)^2}[/tex]
[tex]D=\sqrt{36+64}[/tex]
D=√100
D=10
the distance is 10 units
