We are given that:
m0 = initial mass of rocket = 25.3 g
t = duration of the burn = 1.90 s
T = average thrust = 5.26 N
mFu = mass of fuel = 12.8 g
First we calculate the final mass after 1.90 s (mF):
mF = m0 – mFu = 25.3 g – 12.8 g = 12.5 g
Then we calculate for the mass rate of fuel consumption, φm:
φm = 12.8 g / 1.90 s =6.737 g /s
To calculate for the average exhaust speed (vF), we use the derived formula:
Δv = [T / φm] * ln(m0/mF)
Since the rocket started from rest, therefore Δv = vF
vF = [T / φm ] * ln(m0/mF)
vF = [5.26 N / 6.737 x 10^-3 kg/s] * ln(25.3 g / 12.5 g)
vF= 550.5 m/s