Respuesta :
v1=4m/s, v2=velocity after 3 sec, average velocity= (v1+v2)/2
v2=a*dt (a=2, dt=3) ==> v2=2*3= 6m/s
v1= 4 m/s
average velocity= (4+6)/2 = 10/2 = 5 m/s
v2=a*dt (a=2, dt=3) ==> v2=2*3= 6m/s
v1= 4 m/s
average velocity= (4+6)/2 = 10/2 = 5 m/s
The average velocity during the acceleration is 5 m/s.
What is acceleration?
Acceleration is defined as the rate change of velocity with time.
acceleration a = (Δv) / (Δt)
A car traveling at 4.0 m/s has a constant acceleration of 2.0 m/s² after 3.0 seconds, the final velocity will be
2 = v/ 3
v = 6.0 m/s
Average velocity = 4.0 + 6.0 /2
V= 10/2
V = 5 m/s
Thus, the average velocity during the acceleration is 5 m/s.
Learn more about acceleration.
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