Answer:
a) V = 15.96 m/s
b) F = 1.06 N
Explanation:
a) Using the conservation of energy:
[tex]E_i = E_f[/tex]
so:
[tex]mgh = \frac{1}{2}mv^2[/tex]
where m is the mass, g the gravity, h the altitude and v the velocity when the baseball hit the ground. So, replacing values:
[tex](0.145kg)(9.8)(13m) = \frac{1}{2}(0.145kg)v^2[/tex]
solving for v:
v = 15.96 m/s
b) If there are air resistance:
[tex]E_i - E_f = W_f[/tex]
so:
[tex]mgh-\frac{1}{2}mv^2 = Fd[/tex]
Where F is the average force and d the distance of fall.
so, replacing the values:
[tex](0.145kg)(9.8)(13m)-\frac{1}{2}(0.145kg)(8m/s)^2 = F(13m)[/tex]
Solving for F:
F = 1.06 N
