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A certain merry-go-round is accelerated uniformly from rest and attains an angular speed of 1.2 rad/s in the first 18 seconds. if the net applied torque is 1200 n · m, what is the moment of inertia of the merry-go-round?

Respuesta :

celai

Moment of inertia is the term specified to rotational inertia which is the rotational equivalent of mass for linear motion. It gives the idea in the relationship for changing aspects of rotational motion the moment of inertia must be stated with respect to a preferred axis of rotation.

Given the following

Net applied torque         = 1200 Nm

Angular acceleration      = 1.2 rad/s / 18 seconds (angular speed over time)

 

Derive the formula: net applied torque = moment of inertia x angular acceleration into moment of inertia = net applied torque over angular acceleration.

Therefore:

I             = 1200 Nm / (1.2 rad/s / 18 seconds)

I             = 18000 kg.m² moment of inertia

arshikhan8123

The moment of inertia of the merry-go-round is 18000 kg.m².

Net applied torque =  1200 Nm.

Angular acceleration = 1.2 rad/s / 18 seconds (angular speed over time).

I = 1200 Nm / (1.2 rad/s / 18 seconds).

I = 18000 kg.m² moment of inertia.

Why is it called the moment of inertia?

The moment of inertia is the quantitative measure of the rotational inertia of a body. The term moment of inertia was first used by Leonhard Euler in his book Theoria in 1765, and later it was incorporated into Euler's second law.

The moment of inertia, in physics, quantitative measure of the rotational inertia of a body i.e., the opposition that the body exhibits to having its speed of rotation about an axis altered by the application of torque (turning force).

Learn more about the moment of inertia here: https://brainly.com/question/14460640

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