The initial population is P₀ = 650,000.
Growth rate, r = 5% per year, or r = 0.05.
Let t = years.
The proposed model is
[tex]P(t)= P_{0}e^{rt} [/tex]
or
[tex]P(t)=650000e^{0.05t}[/tex]
Therefore
[tex] \frac{P}{650000} =e^{0.05t}[/tex]
ln(P/650000) = 0.05t
When P = 1,000,000
0.05t = ln(1000000/650000) = 0.4308
t = 8.6157 years = 2 years (approx)
Answer: 2 years (approx)