Respuesta :
[tex] 6x^2 + 432 = 0\\
x^2+72=0\\
x^2=-72[/tex]
No real solutions.
Complex solutions
[tex]x=-\sqrt{-72} \vee x=\sqrt{-72}\\ x=-6\sqrt 2 i \vee x=6\sqrt 2 i[/tex]
No real solutions.
Complex solutions
[tex]x=-\sqrt{-72} \vee x=\sqrt{-72}\\ x=-6\sqrt 2 i \vee x=6\sqrt 2 i[/tex]
Answer:
The possible values of x are:
[tex]x=6\sqrt{2}i\ and\ x=-6\sqrt{2}i[/tex]
Step-by-step explanation:
We are given a quadratic equation in terms of variable ''x'' as:
[tex]6x^2+432=0[/tex]
This equation could also be written as:
[tex]6(x^2+72)[/tex]
Since we take out 6 common both the terms as both the terms are a multiple of ''6''.
Hence, we get:
[tex]x^2+72=0\\\\i.e.\\\\x^2=-72\\\\\\i.e.\\\\\\x=\pm \sqrt{-72}\\\\\\i.e.\\\\\\x=\pm 6\sqrt{2}i[/tex]
Hence, the possible values of x are:
[tex]x=6\sqrt{2}i\ and\ x=-6\sqrt{2}i[/tex]