Respuesta :
The circles that have their centers in the third quadrant are choices B and D. The original formula of a circle is (x - h)² + (y - k)² = r² where h is the value of the abscissa, k is the value of the ordinate and r is the radius of the circle. h and k are the exact coordinate of the center of the circle. So,
B.(x + 9)² + (y + 12)² = 36
[x - (-9)]² + [y - (-12)]² = 6²
C(-9, -12)
D.(x + 16)² + ( y + 3)² = 17
[x - (-16)]² + [y - (-3)]² = √17
C(-16, -3)
B.(x + 9)² + (y + 12)² = 36
[x - (-9)]² + [y - (-12)]² = 6²
C(-9, -12)
D.(x + 16)² + ( y + 3)² = 17
[x - (-16)]² + [y - (-3)]² = √17
C(-16, -3)