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The length of rectangular field is 7 m less than 4 times the width. The perimeter is 136 m. Find the width and length

Respuesta :

P = 2(L + W)
P = 136
L = 4W - 7

136 = 2(4W - 7 + W)
136 = 2(5W - 7)
136 = 10W - 14
136 + 14 = 10W
150 = 10W
150/10 = W
15 = W <=== width is 15 m

L = 4W - 7
L = 4(15) - 7
L = 60 - 7
L = 53 <== length is 53 m

Answer:

15 m and 53 m.

Step-by-step explanation:

Let the length of the rectangular field = x m

and width = y m

From the statement "Length is 7m less than 4 times the width"

x = 4y - 7 ----------(1)

"perimeter of the field is 136 m."

2 (x + y) = 136

x + y = 68 ---------(2)

Now we replace the value of x from equation 1 to 2

4y - 7 + y = 68

5y - 7 = 68

5y = 68 + 7 = 75

y = 15 m

From equation (2)

x + 15 = 68

x = 68 - 15

  = 53 m

Therefore, length and width of the field are 15 m and 53 m.