Respuesta :
15 mins = 900 s
We need to find all common multiples of 18 and 42 less than or equal 900.
We'll find the least common multiple first.
18|2
9|3
3|3
1
42|2
21|3
7|7
[tex]\text{lcm}(18,42)=2\cdot3^2\cdot7=126[/tex]
Now, we nned to find all multiples of 126 that are less than or equal 900.
Those are 126,252,378,504,630,756,882. There are 7 of those.
Therefore the answer is 7.
We need to find all common multiples of 18 and 42 less than or equal 900.
We'll find the least common multiple first.
18|2
9|3
3|3
1
42|2
21|3
7|7
[tex]\text{lcm}(18,42)=2\cdot3^2\cdot7=126[/tex]
Now, we nned to find all multiples of 126 that are less than or equal 900.
Those are 126,252,378,504,630,756,882. There are 7 of those.
Therefore the answer is 7.
15 minutes = 900 seconds
so basically, we would have to find the common multiples of 18 and 42....going all the way to 900
I am not gonna list all the multiples of 18 and 42.....but the common multiples of both are : 126,252,378,504,630,756,882 ...thats 7 numbers
therefore, he will do jumping jacks and whistle (at the same time ) 7 times during the 15 minute period
so basically, we would have to find the common multiples of 18 and 42....going all the way to 900
I am not gonna list all the multiples of 18 and 42.....but the common multiples of both are : 126,252,378,504,630,756,882 ...thats 7 numbers
therefore, he will do jumping jacks and whistle (at the same time ) 7 times during the 15 minute period