Respuesta :
Number of moles of solute contained in a solution of molarity M and volume V litres is
MV.
Here
M=0.85, V=250/1000=0.25L
number of moles of solute = 0.85*0.25=0.4125 mol
MV.
Here
M=0.85, V=250/1000=0.25L
number of moles of solute = 0.85*0.25=0.4125 mol
Explanation:
Molarity is defined as the number of moles of solute present in liter of solution.
Mathematically, Molarity =[tex]\frac{no. of moles}{Volume in liter}[/tex]
The given data is as follows.
V = 250.0 ml = 0.25 L, M = 0.85 M
Therefore, calculate the no. of moles as follows.
No. of moles = Molarity × Volume
= 0.85 M × 0.25 L
= 0.2125 mol
Thus, we can conclude that number of moles present in given solution is 0.2125 mol.