Respuesta :
hello :
2x² = 2
x²=1
x²-1=0
(x-1)(x+1) = 0
x-1=0 or x+1=0
x=1 or x= -1...(answer : B. There are two solutions: -1 and 1 )
2x² = 2
x²=1
x²-1=0
(x-1)(x+1) = 0
x-1=0 or x+1=0
x=1 or x= -1...(answer : B. There are two solutions: -1 and 1 )
Answer:
There are two solutions : -1 and 1.
Step-by-step explanation:
We are given equation in terms of variable x as:
[tex]2x^2=2[/tex]
On dividing both side of the equation by 2 we get the equation as:
[tex]x^2=1[/tex]
This could also be written as:
[tex]x^2-1=0[/tex]
which is further written as:
[tex](x-1)(x+1)=0[/tex]
( Since, we have:
[tex]a^2-b^2=(a-b)(a+b)[/tex] )
Hence, we have:
[tex]x=1\ and\ x=-1[/tex]
Hence, the graph of this equation ( i.e. [tex]x^2-1=0[/tex] )will be point of intersection of:
[tex]y=x^2-1[/tex] and [tex]y=0[/tex]
