Respuesta :

2x^2 + 16x + 50 = 0

divide through by 2:-

x^2 + 8x + 25 = 0

(x + 4)^2 - 16 + 25 = 0

(x + 4)^2  =  -9 

x+4  = 3i  or -3i

x =  -4 + 3i ,  -4 - 3i
This equation has no intersections with the X-axis.

2x^2+16x+50=0 divide by 2
x^2+8x+25=0 subtract 9 from both sides
x^2+8x+16=-9 complete the square
(x+4)^2=-9 square root both sides
x+4 = 3i you get an imaginary number, thus there are no real numbers that will fulfill the above equation. Graphing calculator will show you the same result.

Otras preguntas