Respuesta :
Answer:
Robyn and Vladimir both are correct.
Step-by-step explanation:
Vladimir says that the equation of the line the passes through points (-5, -3) and (10,9) is y = [tex]\frac{4}{5}[/tex] x + 1
Let's find the equation of line
Slope of the line passing through ( -5, -3 ) and (10, 9 )
[tex]m=\frac{y-y'}{x-x'}=\frac{9+3}{10+5}=\frac{12}{15}=\frac{4}{5}[/tex]
So equation will be y = [tex]\frac{4}{5}[/tex]x + c
Since the line passes through (-5, -3)
so (-3) = [tex]\frac{4}{5}[/tex]x (-5) + c
(-3) = -4 + c
c = -3 +4 = 1
So equation should be y = [tex]\frac{4}{5}[/tex]x +1
Therefore, Vladimir is correct.
Robyn says this line is passing through (-10,-7) and (-15, -11)
Slope [tex]m=\frac{y-y'}{x-x'}=\frac{-11+7}{15+10}=\frac{-4}{-5}=\frac{4}{5}[/tex]
equation is y = [tex]\frac{4}{5}[/tex]x + c
Since this line passes through (-10 -7)
so (-7) = [tex]\frac{4}{5}[/tex]x (-10) + c
-7 = -8 + c ⇒ c = 8 - 7 = 1
Equation of the line will be y = [tex]\frac{4}{5}[/tex]x + 1
So Robyn and Vladimir both are correct.
Answer:
Both of them are correct
Step-by-step explanation:
Given the equation: y = (4/5)*x + 1, we want to check if some points belongs to it. To do so, just replace the coordinates of the point in the equation and check if the equality is satisfied.
Point (-5, -3)
-3 = (4/5)*(-5) + 1
-3 = -3 -> equation satisfied
Point (10, 9)
9 = (4/5)*10 + 1
9 = 9 -> equation satisfied
Then, Vladimir is correct
Point (-10, -7)
-7 = (4/5)*(-10) + 1
-7 = -7 -> equation satisfied
Point (-15, -11)
-11 = (4/5)*(-15) + 1
-11 = -11 -> equation satisfied
Then, Robyn is correct.
