Respuesta :
Question:
If
GCD(A,B)>1
GCD(B,C)>1
GCD(C,A)>1
is it *always* true that GCD(A,B,C)>1 ?
Answer: no
Following is a counter example: A=6=2*3, B=14=2*7, C=21=3*7
There is no GCD greater than 1 that divides ALL of A, B and C.
I am sure you will be able to find other counter examples.
If
GCD(A,B)>1
GCD(B,C)>1
GCD(C,A)>1
is it *always* true that GCD(A,B,C)>1 ?
Answer: no
Following is a counter example: A=6=2*3, B=14=2*7, C=21=3*7
There is no GCD greater than 1 that divides ALL of A, B and C.
I am sure you will be able to find other counter examples.
Answer:
No, It is not necessarily true that the greatest common divisor of all three numbers is greater than 1.
Step-by-step explanation:
Consider the provided information.
It is given that Aisha's number and Benoit's number have a common divisor greater than 1.
Let us assume any number having common divisor greater than 1
Let say Aisha's number is 10 and Benoit's number is 14.
Now the common divisor in both the numbers are:
Aisha: 10 = 2×5
Benoit: 14 = 2×7
Here, the common divisor is 2.
Now, it is given that Aisha's number and Carleen's number also have a common divisor greater than 1.
Let us assume Carleen's number is 35. Thus the common divisor in both the numbers are:
Aisha: 10 = 2×5
Carleen: 35 = 5×7
Here, the common divisor is 5.
Benoit's number and Carleen's number also have a common divisor greater than 1.
Benoit: 14 = 2×7
Carleen: 35 = 5×7
Here, the common divisor is 7.
Now, we need to find that the greatest common divisor of all three numbers is greater than 1.
Aisha: 10 = 2×5
Benoit: 14 = 2×7
Carleen: 35 = 5×7
There is no common divisor greater than 1.
Hence, it is not necessarily true that the greatest common divisor of all three numbers is greater than 1.