tan x= sin x/cos x. Therefore, tan (90-A)°= ? (All angle measurements are in degrees)
a.) 1/tan(90-A)
b.) 1/sin A
c.) 1/cos(90-A)
d.) 1/tan A

In the first quadrant, tangent, sine and cosine function are all positive.

So tan(90-A) = sin(90-A) / cos(90-A) = cos(A) / sin(A) = 1/tan(A)

Answer is d

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abidemiokin abidemiokin · Answer 2 · 2022-02-21T13:25:35+01:00

abidemiokin abidemiokin

21-02-2022

The value of tan(90-A) is tan A

Trigonometry identity

Given the expression

tan x = sinx/cos x

The expression tan(90-A) will be written as:

tan(90-A) = sin(90-A)/cos(90-A)

Recall that sin (90-A) = sinA
cos(90-A) = cosA

Therefore:

tan(90 - A) = sinA/cosA = tanA

Hence the value of tan(90-A) is tan A
Learn more on trigonometry here: https://brainly.com/question/24349828

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tan x= sin x/cos x. Therefore, tan (90-A)°= ? (All angle measurements are in degrees) a.) 1/tan(90-A) b.) 1/sin A c.) 1/cos(90-A) d.) 1/tan A

Respuesta :

Trigonometry identity

Otras preguntas

tan x= sin x/cos x. Therefore, tan (90-A)°= ? (All angle measurements are in degrees)
a.) 1/tan(90-A)
b.) 1/sin A
c.) 1/cos(90-A)
d.) 1/tan A