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The length of a rectangle is 120 m. The diagonal measures 130 m.



Use this information to find the values of the perimeter and area of the rectangle.

Perimeter of the rectangle: ____ meters

Area of the rectangle: ____ square meters

The length of a rectangle is 120 m The diagonal measures 130 m Use this information to find the values of the perimeter and area of the rectangle Perimeter of t class=

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musiclover10045

Diagonal is sqrt (l^2 +W^2)

Length = 120

Diagonal = 130

 

130 = sqrt ( 120^2 +w^2)

130^2 = w^2 +120^2

16900 = w^2 + 14400

W^2 = 2500

w = sqrt(2500)

W=50

 Perimeter = 240 +100 = 340 meters

Area = 120 x 50 = 6000 sq meters
Width of the rectangel is  found by using Pythagoras theorem

w^2 = 130^2 - 120^2 =  2500

width w  = sqrt 2500 = 50 m

Perimeter of rectangle = 2*120 + 2*50 = 340 m

Area of the rectangle = 50 * 120  =  6000 m^2

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