Answer:
E = 196 joules
Explanation:
It is given that,
Mass of the block, m = 10 kg
At the top, the block will have only potential energy which is given by :
[tex]P=mgh[/tex]
At the bottom of the inclined plane, it will have only kinetic energy which is given by :
[tex]E=\dfrac{1}{2}mv^2[/tex]
Applying the conservation of energy as :
[tex]E=\dfrac{1}{2}mv^2=mgh[/tex]
[tex]E=10\ kg\times 9.8\ m/s^2\times 2\ m[/tex]
E = 196 joules
So, the block will have 196 joules of kinetic energy when it reaches the bottom. Hence, this is the required solution.
