This is an example of a permutation problem.
Since there are three digits, the total number of
possibilities would be:
total number of possibilities = (amount of numbers that
can take up hundreds place) * (amount of numbers that can take up tens place) *
(amount of numbers that can take up ones place)
It is given that there is only one number that can take
up the hundreds and ones place, 7 and 1 respectively. For the tens place, there
are ten numbers that can take this place (0 to 9), therefore:
total number of possibilities = 1 * 10 * 1
total
number of possibilities = 10
There are 10 positive three -digit integers.
