Respuesta :
[tex]cos(\theta) = x/\sqrt{x^2+y^2} = x/r, and r = \sqrt{ x^2+y^2} so
r = 3 - x/r ==> r^2 + 3r + x = 0,
[\tex]
r = solutions of quadratic and finally
[tex]
r = \sqrt{ x^2+y^2} = solutions,
[\tex]
you could eventually write y(x)! Not sure you're still looking at this question though! ?:)
r = 3 - x/r ==> r^2 + 3r + x = 0,
[\tex]
r = solutions of quadratic and finally
[tex]
r = \sqrt{ x^2+y^2} = solutions,
[\tex]
you could eventually write y(x)! Not sure you're still looking at this question though! ?:)
The rectangular coordinates is x²+ x + y² - 3√x² + y² =0
What is Polar equation?
Polar coordinates are a complementary system to Cartesian coordinates, which are located by moving across an x-axis and up and down the y-axis in a rectangular fashion. While Cartesian coordinates are written as (x,y), polar coordinates are written as (r,θ).
In polar coordinates, a point in the plane is determined by its distance r from the origin and the angle theta (in radians) between the line from the origin to the point and the x-axis
The polar coordinate system is a two-dimensional coordinate system in which each point on a plane is determined by a distance from a reference point and an angle from a reference direction
Given:
r = 3 − cos θ
as, the standard form:
x=r cos(θ)
So, r= 3- x/r
r² + 3r + x=0
We know: r= √ x² + y²
So, the rectangular coordinates is x²+ x + y² - 3√x² + y² =0
Learn more about this concept here:
https://brainly.com/question/4308638
#SPJ2
