Respuesta :
Answer : The mass of sulfur and oxygen are present in second sample is, 115.44 and 212.72 grams respectively.
Solution :
As we know that the component of elements are in fixed proportions in the compound.
First we have to calculate the total mass of first sample.
Total mass of first sample = 2.02 + 32.07 + 64 = 98.04 g
Now we have to calculate the % of hydrogen, sulfur and oxygen.
[tex]\% \text{ of H}=\frac{\text{Mass of H}}{\text{Total mass of sample}}\times 100=\frac{2.02g}{98.04g}\times 100=2.06\%[/tex]
[tex]\% \text{ of S}=\frac{\text{Mass of S}}{\text{Total mass of sample}}\times 100=\frac{32.07g}{98.04g}\times 100=32.71\%[/tex]
[tex]\% \text{ of O}=\frac{\text{Mass of O}}{\text{Total mass of sample}}\times 100=\frac{64g}{98.04g}\times 100=65.27\%[/tex]
Now we have to calculate the total mass of second sample.
[tex]\% \text{ of H}=\frac{\text{Mass of H}}{\text{Total mass of second sample}}\times 100\\\\2.06\%=\frac{7.27g}{\text{Total mass of second sample}}\times 100\\\\\text{Total mass of second sample}=352.91g[/tex]
Now we have to calculate the mass of sulfur and oxygen.
[tex]\% \text{ of S}=\frac{\text{Mass of S}}{\text{Total mass of second sample}}\times 100\\\\\text{Mass of S}=32.71\times \frac{352.91}{100}=115.44g[/tex]
[tex]\% \text{ of O}=\frac{\text{Mass of O}}{\text{Total mass of second sample}}\times 100\\\\\text{Mass of O}=65.27\times \frac{352.91}{100}=212.72g[/tex]
Therefore, the mass of sulfur and oxygen are present in second sample is, 115.44 and 212.72 grams respectively.
115,420 grams of sulfur and 230, 336 grams of oxygen are present in a second sample of h2so4 containing 7.27 g of hydrogen
Further explanation
Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements
In the same compound, although from different sources and formed by different processes, it will still have the same composition/comparison
With this law, we can calculate how many grams an element is needed to make a compound with a certain mass, as desired
The mass of compounding compounds can also be calculated.
For example, the mass ratio of oxygen (O) and hydrogen (H) elements in H₂O remains at 8: 1. So if you know the amount of mass of oxygen you can know the amount of hydrogen and water mass.
It is known that the mass ratio of H₂SO₄ compounds is:
H = 2.02 grams
S = 32.07 grams
O = 64 grams
So that the mass ratio of the three elements is: (we divide by the smallest mass of element H by 2.02 g)
H: S: O = 1: 15,876: 31,68
From the second H₂SO₄ sample it is known that the mass H is 7.27 grams, then the mass of the other elements:
S = 15,876 x 7.27 = 115,420 grams
O = 31.68 x 7.27 = 230, 336 grams
Learn more
scientist’s law about the ratios of masses
https://brainly.com/question/2844503
Carbon tetrachloride
https://brainly.com/question/9274824
two different compounds of sulfur and fluorine.
https://brainly.com/question/2094960
Keywords: H₂SO₄, The mass of compounding compounds, Proust, Comparative Law
