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On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 94.5 cm and diameter 2.00 cm from a storage room to a machinist. calculate the weight of the rod, w. the acceleration due to gravity, g = 9.81 m/s2 .

Respuesta :

The volume of a cylinder is PI*R^2H where PI is a regular, R is the radius and H the height. Consequently, the quantity of the iron rod could be (3.141)*((2.05/2)^2)*(ninety four.Three) = 311.2 cm^three. The density of Iron is 7.874 gm/cm^3, so the whole weight would be 2449 grams, or about 2.5 kilograms.        

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