School meeting was attended only by sophomores, juniors, and seniors. 5/12 of those who attended were juniors, and 1/3 were seniors. If 36 sophomore attended, what was the total number of students who attended the meeting ??
If [tex] \frac{9}{12} [/tex] of students were juniors and seniors that leaves the 36 sophomores to be [tex] \frac{3}{12} [/tex] or [tex] \frac{1}{4} [/tex] of attendees. I got [tex] \frac{9}{12} [/tex] by converting [tex] \frac{1}{3} to \frac{4}{12} by multiplying it by 4[/tex] and adding it to [tex] \frac{5}{12} [/tex].
Now if 36 is [tex] \frac{3}{12} [/tex] of the equation that means theirs at least 36 juniors and seniors.
Lets start with seniors. there should be just over 36 of them there. Lets start by multiplying 36 by [tex] \frac{3}{12} [/tex] to figure out how many [tex] \frac{1}{12} [/tex] is. The equation would look like this 36*(3/12) start with 3/12. this equals .25 or [tex] \frac{1}{4} [/tex]. Now multiply 36 by .25. this equals 9.
We have 9 students per [tex] \frac{1}{12} [/tex] of the attendees.
To get the amount of seniors add 9 to 36 [tex] \frac{4}{12} [/tex] because we already stated [tex] \frac{3}{12} [/tex] is 36. 36+9=45
Now to find the juniors add another 9 to create [tex] \frac{5}{12} [/tex]. 45+9=54
In total you have: 36 sophomores 54 juniors 45 seniors
