Respuesta :

Answer:

[tex]g(x)=-\sqrt{x+3}+8[/tex]

Step-by-step explanation:

we have

[tex]f(x)=-2\sqrt{x-3}+8[/tex]

using a graphing tool

see the attached figure N [tex]1[/tex]

The domain is the interval ------> [3, ∞)

The range is the interval ------> (-∞, 8]

Verify the range of each case by graphing tool

see the attached figure N [tex]2[/tex]

case A) [tex]g(x)=\sqrt{x-3}-8[/tex]

The range is the interval ------> [-8,∞)

case B) [tex]g(x)=\sqrt{x-3}+8[/tex]

The range is the interval ------> [8,∞)

case C) [tex]g(x)=-\sqrt{x+3}+8[/tex]

The range is the interval ------>(-∞, 8] ----> is the solution (same range that f(x))

case D) [tex]g(x)=-\sqrt{x-3}-8[/tex]

The range is the interval ------> (-∞, -8]

Ver imagen calculista
Ver imagen calculista

The function that has the same range as given in the image above is  g (x) = -[tex]\sqrt{x + 3 + 8}[/tex].

What is the range of the function?

The range of a function is known to be the composition of all its possible outcome values.

In the above, the  function g (x) = -[tex]\sqrt{x + 3 + 8}[/tex]  is known to have similar range as given in the image because in graphing of the radical function, it would be similar to  g (x) = -[tex]\sqrt{x + 3 + 8}[/tex] .

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