Respuesta :

Answer:

[tex]5\sqrt{10}\ units[/tex]

Step-by-step explanation:

Let

x------> the length of one leg of the triangle

we know that

In the right triangle of the figure

[tex]cos(45\°)=\frac{x}{10\sqrt{5}}[/tex]

and remember that

[tex]cos(45\°)=\frac{\sqrt{2}}{2}[/tex]

so

[tex]\frac{\sqrt{2}}{2}=\frac{x}{10\sqrt{5}}[/tex]

[tex]x=(\sqrt{2}*10\sqrt{5})/2[/tex]

[tex]x=5\sqrt{10}\ units[/tex]

The length of one leg of the triangle [tex]\boxed{5\sqrt {10} }.[/tex]

Further explanation:

The Pythagorean formula can be expressed as,

[tex]\boxed{{H^2} = {P^2} + {B^2}}.[/tex]

Here, H represents the hypotenuse, P represents the perpendicular and B represents the base.

Isosceles triangle has 2 sides equal to each other and the two base angles are equal to each other.

Given:

The length of the hypotenuse is [tex]10\sqrt 5.[/tex]

The options are as follows,

(A). [tex]5\sqrt 5[/tex]

(B). [tex]5\sqrt {10}[/tex]

(C). [tex]10\sqrt {5}[/tex]

(D). [tex]10\sqrt {10}[/tex]

Explanation:

The length of the hypotenuse is [tex]10\sqrt 5.[/tex]

Consider the length of other leg of the triangle [tex]x[/tex].

Use the Pythagoras formula in triangle ABC.

[tex]\begin{aligned}{\left( {10\sqrt 5 }\right)^2}&= {\left( x \right)^2} + {\left( x \right)^2}\\100 \times 5&= 2{x^2}\\\frac{{500}}{2}&= {x^2}\\250&= {x^2}\\\end{aligned}[/tex]

Further solve the above equation.

[tex]\begin{aligned}{x^2}&= 250\\x&= \sqrt {250}\\x&= 5\sqrt {10} \\\end{aligned}[/tex]

Hence, the length of one leg of the triangle [tex]\boxed{5\sqrt {10} }.[/tex]

Option (A) is not correct.

Option (B) is correct.

Option (C) is not correct.

Option (D) is not correct.

Learn more:

1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.

2. Learn more about equation of circle brainly.com/question/1506955.

3. Learn more about range and domain of the function https://brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Trigonometry

Keywords: length of the leg, triangle, isosceles,perpendicular bisectors, sides, right angle triangle, triangle, altitudes, hypotenuse, on the triangle, hypotenuse, trigonometric functions, Pythagoras theorem, formula.