draw a figure of the problem, check the picture attached.
Let C represent the position of the arm of Stacey, and E represent the position of the neck of the dog. Let B be the point such that CB=30 ft, and measure of angle CBE is 90 degrees.
The distance of Stacey from the dog is BE and can be found by the formula:
[tex]tan(CEB)= \frac{CB}{BE} [/tex]
[tex]tan10 ^{o} = \frac{30}{|BE|} [/tex]
[tex]|BE|= \frac{30}{tan10}= \frac{30}{0.176}=170.5 [/tex] feet
