If the area of a rectangle is 16s^2t and the length is 8st^2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.
Area = Length x Width Substituting the given values: 16S^2 t = 8St^2 x Width Manipulating for Width: Width = 16S^2 t / 8St^2 Rewriting the squared terms in simplified form : Width = 16 x S x S x t / 8 x S x t x t Cancelling the like terms Width = 16 x S / 8 x t Cancelling the numeric terms :
