Answer:
Given Equation : x² = 8y
Given Equation matches with standard equation of parabola on positive y-axis
x² = 4ay
By comparing both equation we get,
4a = 8 ⇒ a = 2
Focus of parabola = ( 0 , 2 )
Vertex of parabola = ( 0 , 0 )
Axis of Symmetry = y-axis
To draw its, we find some points
when x = 4 or -4 we get
4² = 8y ⇒ 16 = 8y ⇒ y = 2
So, points are ( 4 , 2 ) and ( -4 , 2 )
when x = 8 or -8 we get
(-8)² = 8y ⇒ 64 = 8y ⇒ y = 8
So, points are ( 8 , 8 ) and ( -8 , 8 )
Graph from above points is attached.
