Problem 1
The largest value would be 1 and the smallest would be
-1.
To get a product of 1, either all are 1 or two of the
variables are -1 and the other one is 1.
Largest value = (1)^2 * (1)^3 * (1)^4 =1
Smallest value = (- 1)^2 * (- 1)^3 * (1)^4 = -1
The difference is:
largest value – smallest value = 1 – (-1) = 2
Therefore the answer is letter D.
Problem 2
% loss = (final price – initial price) * 100%/ initial
price
where, final price per dozen = ( $2.50 / piece) (12 piece
/ dozen) = $30
Therefore,
% loss = ($30 - $33) * 100 / $33
% loss = - 300/ 33 = 9 1/11
Therefore the answer is letter C.
