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i need j to solve i solved rest , pls answere fast i need help to submit in school ty


a High School wants to double the size (area) of its parking lot by expanding the existing lot as shown. By what distance, x, should the lot be expanded? Answer the questions below to help work towards the answer.


a) What is the area of the school? 49500Correct. square feet

b) What is the area of the school and the old lot combined? 90000Correct. square feet

c) What is the area of just the old lot? 40500Correct. square feet

d) What does the area of the new lot need to be? 40500Correct. square feet (**Hint** The total parking should be twice the old lot)

e) What is the total area of the school combined with all the parking? 130500Correct. square feet

f) Write an equation to solve for x. (x+240)(x+375)=130500Correct. (**Hint** length of entire space time width of entire space = total area)

g) Simplify the equation above so that one side is equal to zero. x^2+615x-40500=0Correct. (use the carrot ^ key to represent an exponent)

h) Factor the above equation. What are the factors? (x-60)(x+675)Correct.

i) Solve the factors above using the zero product property. What is the solution for x? 60Correct. feet

j) What are the dimensions of the entire space with the expansion? 300 , 435Incorrect.

i need j to solve i solved rest pls answere fast i need help to submit in school ty a High School wants to double the size area of its parking lot by expanding class=

Respuesta :

To find the dimensions of the entire space with the expansion, we need to consider the dimensions of the old lot and the expansion.

First, let's recall that the area of a rectangle is given by its length multiplied by its width.

We know the area of the old lot is 40500 square feet. Since the length and width of the old lot are not given, let's represent them as L and W, respectively.

So, we have the equation L * W = 40500.

Now, we need to double the area of the old lot to find the area of the new lot, which is 40500 square feet. This means the area of the new lot should be 2 * 40500 = 81000 square feet.

Since the length of the new lot is x feet, we can write the equation (L + x) * W = 81000.

Simplifying the equation, we get L * W + x * W = 81000.

Since we already know L * W = 40500, we can substitute this value into the equation: 40500 + x * W = 81000.

We also know that the area of the school combined with all the parking is 130500 square feet. So, we have the equation (L + x) * (W + 240) = 130500.

Expanding the equation, we get L * W + 240L + x * W + 240x = 130500.

Since L * W = 40500, we can substitute this value into the equation: 40500 + 240L + x * W + 240x = 130500.

Now, let's substitute the value of x * W from the previous equation: 40500 + 240L + 81000 + 240x = 130500.

Combining like terms, we get 240L + 240x = 90000.

Now, let's simplify the equation further by factoring out 240: 240(L + x) = 90000.

Dividing both sides by 240, we get L + x = 375.

Since the length of the old lot is not given, we cannot determine the exact dimensions of the entire space with the expansion.

Therefore, we cannot determine the dimensions of the entire space with the expansion based on the information provided in the question.

If you have any further questions, feel free to ask.

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