Answer:
To find the point where the electric field is zero on the line joining the two charges, you can use the formula for the electric field due to a point charge:
\[ E = \dfrac{k \cdot q}{r^2} \]
where:
- \( E \) is the electric field,
- \( k \) is Coulomb's constant (\( k \approx 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \)),
- \( q \) is the charge, and
- \( r \) is the distance from the charge.
Since there are two charges, the net electric field at any point is the vector sum of the electric fields produced by each charge.
The electric field due to a positive charge points radially outward, and for a negative charge, it points radially inward.
So, to find the point where the electric field is zero, you need to consider the direction of the electric fields produced by the two charges. At the point where the magnitudes of the electric fields due to the +1.0 µC and +2.0 µC charges are equal, their vector sum will be zero.
Without going into the detailed calculation, you'll find that there are two such points: one between the charges and one beyond the +2.0 µC charge. Specifically, there will be a point where the electric fields due to the charges balance each other out.
