A high jumper, falling at 4.0 m/s, lands on a foam pit and comes to rest, compressing the pit 0.4 m. If the pit is able to exert a net force of 1200 N on the high jumper in breaking the fall, what is the jumper’s mass? (60 kg)

Respuesta :

60 kg.

The problem involves the concept of weight and gravitational force.

Step 1: Calculate the weight of the barbell using the formula W = mg, where W is the weight, m is the mass, and g is the acceleration due to gravity.

Given: m = 50.0 kg, g = 9.8 m/s^2.

W = 50.0 kg * 9.8 m/s^2 = 490 N.

The problem involves the concept of work and energy.

Step 1: Calculate the work done by the foam pit on the high jumper using the formula W = Fd, where W is the work done, F is the force, and d is the distance.

Given: F = 1200 N, d = 0.4 m.

W = 1200 N * 0.4 m = 480 J.

Step 2: Calculate the kinetic energy of the high jumper before landing using the formula KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass, and v is the velocity.

Given: v = 4.0 m/s.

KE = 0.5 * m * (4.0 m/s)^2 = 8.0 m^2/s^2 * m = 8.0 m^2/s^2 * kg.

Step 3: Equate the work done by the foam pit to the change in kinetic energy of the high jumper.

480 J = 8.0 m^2/s^2 * kg.

Step 4: Solve for the mass of the high jumper.

m = 480 J / (8.0 m^2/s^2) = 60 kg.