Answer:
8
Step-by-step explanation:
You want the ratio of the volumes of a container 32 m by 16 m by 8 m, and one that is 8 m cubed.
Volume
The volume of each container is the product of its dimensions:
V = LWH
Then the volumes are ...
large container V = (32 m)(16 m)(8 m)
small container V = (8 m)(8 m)(8 m)
The number of times a small container can be filled from the large one is the ratio of their volumes:
[tex]\dfrac{\text{large volume}}{\text{small volume}}=\dfrac{(32\text{ m})(16\text{ m})(8\text{ m})}{(8\text{ m})(8\text{ m})(8\text{ m})}=(4)(2)(1) = 8[/tex]
The small container can be filled 8 times.
