a) [tex]\dfrac{2}{\sqrt3}=\dfrac{2\sqrt3}{\sqrt3\times\sqrt3}=\dfrac{2\sqrt3}{3}[/tex]
b) [tex]\dfrac{7}{2\sqrt5}=\dfrac{7\sqrt5}{2\sqrt5\times\sqrt5}=\dfrac{7\sqrt5}{10}[/tex]
c) [tex]\dfrac{\sqrt3}{4\sqrt2}=\dfrac{\sqrt3\times\sqrt2}{4\sqrt2\times\sqrt2}=\dfrac{\sqrt6}{8}[/tex]
d) [tex]\dfrac{3\sqrt3}{\sqrt8}=\dfrac{3\sqrt3\times\sqrt8}{\sqrt8\times\sqrt8}=\dfrac{3\sqrt{24}}{8}=\dfrac{3\sqrt{2^2\times6}}{8}=\dfrac{6\sqrt6}{8}=\dfrac{3\sqrt6}{4}[/tex]
