vectors - can you help me with question 4b please!!!!! will mark brainliest!!! please can you explain too

First, let's break down the given displacements into their horizontal (x) and vertical (y) components. We can use trigonometry to determine these components.
For the displacement of 26 km on a bearing of 175°:
The horizontal component (x) can be found using the cosine function:
x = 26 km * cos(175°)
x ≈ -23.63 km (rounded to two decimal places, as specified by the problem)
The vertical component (y) can be found using the sine function:
y = 26 km * sin(175°)
y ≈ -6.87 km (rounded to two decimal places)
Similarly, for the displacement of 18 km on a bearing of 294°:
The horizontal component (x) can be found using the cosine function:
x = 18 km * cos(294°)
x ≈ 5.46 km (rounded to two decimal places)
The vertical component (y) can be found using the sine function:
y = 18 km * sin(294°)
y ≈ -15.32 km (rounded to two decimal places)
Now, we can add the horizontal and vertical components separately to find the resultant displacement.
Horizontal component: -23.63 km + 5.46 km ≈ -18.17 km (rounded to two decimal places)
Vertical component: -6.87 km + (-15.32 km) ≈ -22.19 km (rounded to two decimal places)
Therefore, the resultant displacement is approximately -18.17 km in the horizontal direction and -22.19 km in the vertical direction.
To represent this graphically, we can draw a Cartesian coordinate system and plot the resultant displacement as a vector with its tail at the origin (0, 0) and its head at (-18.17, -22.19).