Respuesta :
Step-by-step explanation:
To determine the total cost of buying and using each car, let's calculate the expenses for each:
1. **Gasoline Cost:**
- Car A: \(50 \text{ miles/month} \times \frac{12 \text{ months}}{1 \text{ year}} \times \frac{1}{20 \text{ miles/gallon}} \times \$3.99/\text{gallon}\)
- Car B: \(50 \text{ miles/month} \times \frac{12 \text{ months}}{1 \text{ year}} \times \frac{1}{24 \text{ miles/gallon}} \times \$3.99/\text{gallon}\)
2. **Purchase Cost + 4 years of estimated repairs:**
- Car A: $8100 + 4 years of repairs
- Car B: $8500 + 4 years of repairs
Let me calculate these values to find out which car will cost Sophia the least.
For Car A:
Gasoline cost per year: \(50 \text{ miles/month} \times 12 \text{ months/year} \times \frac{1}{20 \text{ miles/gallon}} \times \$3.99/\text{gallon} = \$119.70/year\)
Total cost for 4 years:
\(8100 + 4 \times 119.70 = 8100 + 478.80 = \$8578.80\)
For Car B:
Gasoline cost per year: \(50 \text{ miles/month} \times 12 \text{ months/year} \times \frac{1}{24 \text{ miles/gallon}} \times \$3.99/\text{gallon} = \$99.88/year\)
Total cost for 4 years:
\(8500 + 4 \times 99.88 = 8500 + 399.52 = \$8899.52\)
So, the total cost for Car A over 4 years is \$8578.80 and for Car B is \$8899.52.
Therefore, Car A will cost Sophia less by:
\(8899.52 - 8578.80 = \$320.72\)
The correct answer is D. Car A will cost less for Sophia, and the difference in cost will be $320.72.