Can someone help me with this please!

Answer:
4 th option
Step-by-step explanation:
Using either of the 30° or 60° angles.
Using the 30° angle
with the sine and cosine ratios and the exact values
sin30° = [tex]\frac{1}{2}[/tex] , cos30° = [tex]\frac{\sqrt{3} }{2}[/tex] , then
sin30° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{AC}{10}[/tex] = [tex]\frac{1}{2}[/tex] ( cross multiply )
2 AC = 10 ( divide both sides by 2 )
AC = 5
and
cos30° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{BC}{10}[/tex] = [tex]\frac{\sqrt{3} }{2}[/tex] ( cross multiply )
2 BC = 10[tex]\sqrt{3}[/tex] ( divide both sides by 2 )
BC = 5[tex]\sqrt{3}[/tex]