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f(x)=9x^4-40x^2+16
The question is asking for the zeros of the function and to describe the behavior of the graph at each zero

Please show steps used.

Respuesta :

Answer:

-2, -2/3, 2/3, 2

Step-by-step explanation:

0 = 9x^4 - 40x^2 + 16

then you complete the square to get

9(x^2 - 20/9)^2 -256/9

and solve it to get roots of

x = -2

x = -2/3

x=2/3

x=2

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