Explanation:
Position is given by the standard equation
d = vo t - 1/2 at^2 where d is distance from the start point
d = 7.5 (2.95) - 1/2 (9.81)(2.95)^2
d = - 20.6 m so the height is 20.6 meters
b) acceleration due to gravity is a constant = 9.81 m/s^2 ( downward)
c) v f = vo + a t
vf = 7.5 + 9.81 ( 2.95) = -21.44 m/s ( or 21.44 m/s downward)
d) at max height v = 0
vf = vo + at
0 = 7.5 - 9.81 t t = .76 sec
