To determine the friction force exerted in the skater, we use Newton's Second law of motion which relates force, acceleration and the mass. It is expressed as follows:
F = m (a)
where
m = mass of the body = 68.5 kg
The acceleration, a, of the moving body is calculated by dividing the initial velocity with the total time. Thus,
a = 2.40 m/s / 3.52 s = 0.682 m/s^2
Substituting the values to the equation of force, we will have
F = m (a) = 68.5 kg ( 0.682 m/s^2 ) = 46.7 N
Thus, the friction force that is being exerted by the ice to the skater ould be 46.7 N.
