A jar contains 5 red marbles and 8 white marbles.
Event A = drawing a white marble on the first draw
Event B = drawing a red marble on the second draw
If two marbles are drawn from the jar, one after the other without replacement, what is P(A and B) expressed in simplest form?

A.3/13
B.10/39
C.5/12
D.8/13

2. The second one depends on the first one, there are two options total number of red marbles is 8 or 7, however we are only interested in the first case where we didn't get the red marble the first draw. so next probability is 17/25

3. The Third draw again depends on the other two but we only need the case where no red balls have been taken out of the bag, so probability is 16/24=4/6=2/3

So to get answer we multiply 9/13*17/25*2/3=102/315

The first draw the probability that you will not get red is, 18/26=9/13

The second one depends on the first one, there are two options total number of red marbles is 8 or 7, however we are only interested in the first case where we didn't get the red marble the first draw. so next probability is 17/25

The Third draw again depends on the other two but we only need the case where no red balls have been taken out of the bag, so probability is 16/24=4/6=2/3

Respuesta :

So to get answer we multiply: 9/13*17/25*2/3=102/315

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So to get answer we multiply: 9/1317/252/3=102/315