The perimeter of the rectangle is 64 yards. What is the area? (5 points)

A rectangle with a width of 12 yards and an unknown measure for the length.

420 square yards

240 square yards

40 square yards

20 square yards

Respuesta :

Answer:

Step-by-step explanation:

64 - 2(12) [2 sides since 2 width sides] = 40/2 = 20 per length

A = L x W

A = 20 x 12

A = 240

msm555

Answer:

240 square yards

Step-by-step explanation:

Let's denote the length of the rectangle as [tex]L[/tex] (in yards) and the width as [tex]W = 12[/tex] yards. The formula for the perimeter ([tex]P[/tex]) of a rectangle is given by:

[tex] P = 2L + 2W [/tex]

Given that the perimeter is 64 yards, we can set up the equation:

[tex] 64 = 2L + 2 \times 12 [/tex]

Simplify the equation:

[tex] 64 = 2L + 24 [/tex]

Subtract 24 from both sides:

[tex] 64-24 = 2L + 24-24 [/tex]

[tex] 40 = 2L [/tex]

Divide by 2:

[tex]\dfrac{ 40}{2} =\dfrac{ 2L}{2} [/tex]

[tex] L = 20 [/tex]

Now that we have the length [tex]L[/tex] (20 yards) and the width [tex]W[/tex] (12 yards), we can find the area ([tex]A[/tex]) of the rectangle using the formula:

[tex] A = L \times W [/tex]

[tex] A = 20 \times 12 [/tex]

[tex] A = 240 \, \textsf{square yards} [/tex]

Therefore, the area of the rectangle is [tex]240[/tex] square yards.